85 years ago

Henry Armstrong vs Phil Furr

Fight Details

  • Date: 23rd September 1940
  • Venue: Griffith Stadium, Washington, DC
  • Title: World Welterweight Title

Fighters

Henry Armstrong

Record: 108-12-8

Weight: 146 lbs

Phil Furr

Record: 41-33-8

Weight: 147 lbs

Fight Summary

On September 23, 1940, at Griffith Stadium in Washington, D.C., Henry Armstrong defended his World Welterweight Title against Phil Furr. The bout was a clear demonstration of Armstrong's superior skills and power, with the champion dominating the fight from start to finish.

The champion began cautiously, feeling out his opponent in the first two rounds. However, the fight quickly turned in his favour once Armstrong found his rhythm. In the third round, he scored his first knockdown of Furr, signalling the beginning of the end.

The fourth round proved decisive. Armstrong unleashed his attack, dropping Furr twice. On the second knockdown, Furr was unable to beat the count, resulting in Armstrong's knockout victory.

The New York Times reported that the fight was a straightforward affair for the champion, who "could hardly have had an easier evening." This victory further cemented Armstrong's reputation as one of the most dominant welterweights of his era.

FAQ

Who won the Henry Armstrong vs Phil Furr fight?

Henry Armstrong won by 4th round knockout.

When did Henry Armstrong vs Phil Furr take place?

Henry Armstrong vs Phil Furr took place on 23rd September 1940.

Where did the Henry Armstrong vs Phil Furr fight take place?

It took place at Griffith Stadium, Washington, DC.

What titles were at stake in the Henry Armstrong vs Phil Furr fight?

Henry Armstrong and Phil Furr fought for the World Welterweight Title.

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